Monday, March 06, 2006

Little Problem

The other day in math class, this little guy came up. For a SIMUW graduate, this should be easy.

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C * C = F   F + C = A   F * C = C
B - F = D B * B = D B + C = D
E ^ E = E

Solve.

Hint: All six letters stand for different values.

P.S. It looks cooler with alpha, beta, gamma, etc., but I don't know how to type them reliably.

8 Comments:

Blogger amirhtlusa said...

they are not integers,
r they? (other wise the problem is quite easy :D)

5:42 PM, March 09, 2006  
Blogger CalcyNinja said...

Why, do you think you have a solution?

9:48 PM, March 09, 2006  
Blogger amirhtlusa said...

no, i didn't think on it, becuase you never specified if the numbers are integers or not...
r they?

5:34 AM, March 10, 2006  
Blogger CalcyNinja said...

yeah.

3:44 PM, March 11, 2006  
Blogger Flying_Iguana said...

everything is 0! except for E, which is 1.

10:36 PM, March 23, 2006  
Blogger Flying_Iguana said...

otherwise B and D are not integers:

F = 1

B - 1 = D

B^2 = B - 1

I think.

10:40 PM, March 23, 2006  
Blogger amirhtlusa said...

and yet your hint was that they all are for diffrent values

although one can easily reach a contradiction, assuming that they all stand for different values, by the first, third and last conditions

9:40 PM, March 24, 2006  
Blogger CalcyNinja said...

It's fairly easy to prove all of them equal to 0 except E, or all of them equal to 1 save one, but that's not an answer.

1:41 PM, March 25, 2006  

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